Найти производные следующих функций y = 2+x4x3 arctg x22 + 4x

Y'=2+x2x3∙arctgx22+4x'=2+x2x3∙arctgx22'+4x'=
=2+x2x3'∙arctgx22+2+x2x3arctgx22'+4∙1x'=
=2+x2'∙x3-x3'∙2+x2x6∙arctgx22+2+x2x3∙11+x222∙x22'+4∙x-1'=
=2x∙x3-3x2∙2+x2x6arctgx22+2+x2x3∙11+x44∙12∙2x+4∙-1∙x-1-1=
=2∙x4-6x2-3x4x6∙arctgx22+2+x2x3∙x1+x44-4x2=
=-6x2-x4x6∙arctgx22+(2+x2)∙xx3∙1+x44-4x2=
=x2-6-x2x6∙arctgx22+2+x2x2∙1+x44-4x2=
=(-6-x2)x4∙arctgx22+(2+x2)x2∙1+x44-4x2